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Yahoo!奇摩知識+ - 分類問答 - 科學常識 - 已解決

微積分問題，有沒有幫我?有4個地方一直都不明

May 3rd 2015, 15:29

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因令x=u^6 6*[(u^3/3)-(u^2/2)+u-ln[u+1 l +C] =6*[(x^(1/2)/3)-(x^(1/3)/2)+x^(1/6) -ln l x^(1/6) +1 l +C] 積分(1/(u+1))du=ln l u+1 l +C 定義你算錯代錯 x=u^6 == x^(1/2)=u^(6*(1/2))=u^3 x=u^6 == x^(1/3)=u^(6*(1/3))=u^2 x=u^6 == x^(1/6)=u^(6*(1/6))=u...

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